Предмет: Химия, автор: nour1642019

Calculate ∆H0r for the reaction between copper (II) oxide and carbon, if carbon monoxide is formed in that reaction.
∆Н0f (CuO) = –162.0 kJ/mol, ∆Н0f (СО) = –110,6 kJ/mol

Ответы

Автор ответа: HelloPrettySim
0

To calculate ∆H0r for the reaction between copper (II) oxide and carbon, we can use the following equation:

∆H0r = ∆H0f (products) - ∆H0f (reactants)

Plugging in the given values, we get:

∆H0r = (-110.6 kJ/mol) - (-162.0 kJ/mol)

= 51.4 kJ/mol

Therefore, ∆H0r for the reaction between copper (II) oxide and carbon is 51.4 kJ/mol.

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