Предмет: Химия, автор: superaleksei12

Сколько метана в литрах при нормальных условиях можно получить из 8 моль ацетата натрия​

Ответы

Автор ответа: dyexfnf
1

Ответ:

Объяснение:

8 моль                                        х л

CH₃COONa      +      NaOH     =  CH₄    +     Na₂CO₃

n = 1 моль                                     n = 1 моль

з РХР бачимо ,що n(CH₃COONa) = n(CH₄) = 8 моль

V(CH₄) = n(CH₄) * Vm = 8 * 22,4  = 179,2 л


superaleksei12: Спасибо
lawskija: допоможіть з хімією будь ласка
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