Предмет: Химия, автор: alinachapygina567

Сколько КОН требуется для приготовления 2кг 5% раствора.

Ответы

Автор ответа: dobriakua

3

Дано:

m р-ра(KOH) = 2 кг = 2000 г

ω(KOH) = 5%

Найти:

m(KOH) - ?

Решение:

1) m(KOH) = ω * m р-ра / 100% = 5% * 2000 / 100% = 100 г,

Ответ: Масса KOH составляет 100 г.

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