Question

срочно решить, геометрия​

Answer 1

$6x^3-24x=0\\6x(x^2-4x)=0\\6x=0,\,x^2-4x=0\\x_1=0,\,x_2=4$

$25x^3-10x^2+x=0\\x(25x^2-10x+1)=0\\x(5x-1)^2=0\\x=0,\,5x-1=0\\x_1=0,\,x_2=0.2$

$x^3+3x^2-4x-12=0\\x^2(x+3)-4(x+3)=0\\(x^2-4)(x+3)=0\\(x-2)(x+2)(x+3)=0\\x-2=0,\,x+2=0,\,x+3=0\\x_1=2,\,x_2=-2,\,x_3=-3$

$x^3-5x^2+9x-45=0\\x^2(x-5)+9(x-5)=0\\(x^2+9)(x-5)=0\\x^2+9=0,\,x-5=0\\x=5$

$2x^4+6x^3-8x^2-24x=0\\2x(x^3+3x^2-4x-12)=0\\2x(x^2(x+3)-4(x+3))=0\\2x(x^2-4)(x+3)=0\\2x(x-2)(x+2)(x+3)=0\\2x=0,\,x-2=0,\,x+2=0,\,x+3=0\\x_1=0,\,x_2=2,\,x_3=-2,\,x_4=-3$

$x^5-2x^4+x^3-8x^2+16x-8=0\\x^3(x^2-2x+1)-8(x^2-2x+1)=0\\(x^3-8)(x-1)^2=0\\x^3-8=0,\,x-1=0\\x_1=2,\,x_2=1$