Question

Помогите пожалуйста 1//16a^2+1//6ab+1//9b^2

Answer 1

$frac{1}{16a^2}+frac{1}{6ab}+frac{1}{9b^2}=(frac{1}{4a})^2+2cdotfrac{1}{4a}cdotfrac{1}{3b}+(frac{1}{3b})^2=(frac{1}{4a}+frac{1}{3b})^2$