Question

решите пж № 1 (2,4,6), № 29 (2)
ДАЮ 50 БАЛОВ

Answer 1

$\frac{8}{ {x}^{2} } - \frac{3}{x} + 2 = \frac{8 - 3x + 2 {x}^{2} }{ {x}^{2} } = \frac{2 {x }^{2} - 3x + 8 }{ {x}^{2} }$

$\frac{4c + 3}{c - 1} - 3 = \frac{4c + 3 - 3(c - 1)}{c - 1} = \frac{4c + 3 - 3c + 3}{c - 1} = \frac{c + 6}{c - 1}$

$m - \frac{25}{m - 5} - 5 = \frac{m(m - 5) - 25 - 5(m - 5)}{m - 5} = \frac{ {m}^{2} - 5m - 25 - 5m + 25}{m - 5} = \frac{ {m}^{2} - 10m}{m - 5}$

$\frac{x + 7}{ {x}^{2} + 4x } - \frac{x + 1}{3x + 12} - \frac{3 - 2x}{3x} = \frac{x + 7}{x(x + 4)} - \frac{x + 1}{3(x + 4)} - \frac{3 - 2x}{3x} = \frac{3(x + 7) - x(x + 1) - (x + 4)(3 - 2x)}{3x(x + 4)} = \frac{3x + 21 - {x}^{2} - x - 3x + 2 {x}^{2} - 12 + 8x}{3x(x + 4)} = \frac{ {x}^{2} + 7x + 9 }{3 {x}^{2} + 12x }$