Предмет: Геометрия, автор: draganstas000

один з кутів ромба дорівнює 120 градусів а діагональ яка виходить з вершини цього кута, дорівнює 10см знайти периметир ромба

zmeura1204: Меньшая диагональ 10, по условию. В ромбе с углами 60°;120° меньшая диагональ равна стороне ромба. Р=4*10=40

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Автор ответа: raisakovpakmash

3

розв'язок задачі і відповіді на фото

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