Question

Пожалуйста решите второй пример. Буду безмерно благодарен.

Answer 1

Ответ:

$\frac{ log_{2}(2) \times 9 - 1 \times (2 \times log_{2}(9) ) + 2 \times log_{2}(2) \times 18 - 1 \times (3 \times log_{2}(9) \times log_{2}(18) ) + 4 \times log_{2}(18)) }{ log_{2}(9) - 1 \times (2 \times log_{2}(18)) }$

$\frac{1 \times 9 - 1 \times (2 \times log_{2}(9) ) + 2 \times log_{2}(2) \times 18 - 1 \times (3 \times log_{2}(9) \times log_{2}(18)) + 4 \times log_{2}(18) }{ log_{2}(9) - 1 \times (2 \times log_{2}(18)) }$

9-1*(2*log2(9))+2*log2(2)*18-1*(3*log2(9)*log2(18))+4*log2(18)

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log2(9)-1*(2*log2(18))

$\frac{9 - 2 log_{2}(9) + (2 \times 1) \times 18 - 1 \times (3 \times log_{2}(9) \times log_{2}(18) ) + 4 \times log_{2}(18) }{ log_{2}(9) - 1 \times (2 \times log_{2}(18)) }$

9-2log2(9)+2*18-1*(3*log2(9)*log2(18))+4*log2(18)

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log2(9)-1*(2*log2(18))

9-2log2(9)+36-1*(3*log2(9)*log2(18))+4*log2(18)

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log2(9)-1*(2*log2(18))

(45-2log2(9))-1*(3*log2(9)*log2(18))+4*log2(18)

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log2(9)-1*(2*log2(18))

$\frac{6ln(3)ln(18) - 4ln(18)ln(2) + 4ln(3)ln(2) - 45ln(2) {}^{2} }{ \frac{ln(2) {}^{2} }{ log_{2}(9) - 2 log_{2}(18) } }$

6ln(3)ln(18)-4ln(18)ln(2)+4ln(3)ln(2)-45ln(2)²

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ln(2)²

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2(-ln(3)+ln(18))

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ln(2)

45ln(2)²-4ln(3)ln(2)+4ln(18)ln(2)-6ln(3)ln(18)

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-2(-ln(3)+ln(18)ln(2)

Ответ:

$\frac{12ln(3) {}^{2} + 2ln(3)ln(2) - 49ln(2) {}^{2} }{2ln(2) \times (ln(3) + ln(2))}$

Приблежённое значение:

≈-3,033385