Question

решит уравнение
$tg(2x - \frac{\pi}{10} ) = 0$
​

Answer 1

Решение:

$tg\Big (2x-\dfrac{\pi}{10} \Big ) = 0$

$2x-\dfrac{\pi}{10} = \pi n$

$2x = \dfrac{\pi}{10} + \pi n$

$x = \dfrac{\pi}{20} + \dfrac{\pi n}{2}~~~~~~~~n \in Z$