Question

сократите дробь:

9р^2-q^2

___________

9р^2+6рq+q^2

Answer 1

$frac{9p^2-q^2}{9p^2+6pq+q^2}=frac{(3p-q)(3p+q)}{(3p)^2+2*3p*q+q^2}=frac{(3p-q)(3p+q)}{(3p+q)^2}=frac{3p-q}{3p+q}$