Question

  2х  +  3   =  3х+1

х-1      х+1   х ^2 -1

Answer 1

$frac{2x}{x-1} + frac{3}{x+1} = frac{3x11}{x^{2}-1}$

2x(x+1)+3(x-1)=3x+1

2x^2+2x+3x-3-3x-1=0

2x^2+2x-4=0

x^2+x-2=0

x1=-2, x2=1

Answer 2

  2х  +  3   =  3х+1

х-1      х+1   х ^2 -1

2x(x+1)+3(x-1)=3x+1

2x^2+2x+3x-3-3x-1=0

2x^2+2x-4=0  :2

x^2+x-2=0

D=1-4*1*(-2)=9=3^2

x1=-1+3/2=1       x2=-1-3/2=-2