Question

y2-10y+25/y2-25 : 10y-50/y2+5y=40
уровне , срочно !!! ​

Answer 1

$\frac{y^2-10y+25}{y^2-25} :\frac{10y-50}{y^2+5y} =40\\\frac{(y-5)^2}{(y-5)(y+5)}*\frac{y(y+5)}{10(y-5)} =40\\\frac{(y-5)^2y(y+5)}{(y-5)(y+5)10(y-5)} =40| y\neq 5; y\neq -5\\\frac{y}{10}=40\\y=400$