Question

СРОЧНО
1. Розв'язати рівняння:

а) x2-9x+14/x2-4=0,

б)2x2-x-3/x2-x-2=0

Answer 1

$\displaystyle\bf\\1)\\\\\frac{x^{2} -9x+14}{x^{2} -4} =0\\\\\\\frac{(x-7)(x-2)}{(x+2)(x-2)} =0\\\\\\(x-7)(x-2)=0 \ \ ; \ \ x\neq -2 \ \ , \ \ x\neq 2\\\\x-7=0\\\\\boxed{x=7}\\\\\\2)\\\\\frac{2x^{2} -x-3}{x^{2} -x-2} =0\\\\\\\frac{2(x-1,5)(x+1)}{(x-2)(x+1)} =0\\\\\\(x-1,5)(x+1)=0 \ \ ; \ \ x\neq 2 \ \ ; \ \ x\neq -1\\\\x-1,5=0\\\\\boxed{x=1,5}$