Question

2arccos(-√3/2)+arcsin √2/2

Answer 1

$\displaystyle\bf\\2arcCos\Big(-\frac{\sqrt{3} }{2} \Big)+arcSin\frac{\sqrt{2} }{2} =2\cdot \frac{5\pi }{6} + \frac{\pi }4}= \frac{5\pi }{3}+\frac{\pi }{4} =\frac{5\pi \cdot 4+\pi \cdot 3}{12}=\\\\\\=\frac{20\pi+3\pi }{12} =\frac{23\pi }{12}$