Question

ПАМАГИТИИИИ!!!!!!!!!!!!!!

Answer 1

$\frac{1}{9} = \frac{1}{ {3}^{2} } = { 3}^{ - 2} \\ \frac{1}{9} = \frac{ {1}^{2} }{{3}^{2} } = {(\frac{1}{3} )}^{2}$