Question

Напишите уравнения реакций:

а) Ge -> GeCl2 -> Ge(OH)2 -> GeO -> GeO2 -> GeBr2

б) Sn -> Sn(NO3)2 -> Sn -> SnO -> SnCl2 -> Sn(OH)2

в) Pb -> PbO -> PbO2 -> PbCl2 -> PbCl4

Answer 1

Ответ:

а) Ge + 2HCl= GeCl2 + H2

GeCl2 +2KOH =Ge(OH)2 + 2KCl

Ge(OH)2=GeO +H2O

2GeO+O2=2GeO2

б) Sn + 2HNO3 = Sn(NO3)2 +H2

Sn(NO3)2 + K2= 2KNO3 + Sn

2Sn +O2 =2SnO

SnO +2HCl = SnCl2 +H2O

SnCl2 +2KOH =Sn(OH)2 +2KCl

в) 2Pb + O2 = 2PbO

2PbO +O2 =2PbO2

PbO2 +2HCl =PbCl2 +H2O

PbCl2 + Cl2= PbCl4