Question

Заполните пропуски:
1) 36х^2 - ... + 9y^2 = (6x - Зу)^2
2) 25n^4 + ... + 64m^8 = (... + 8m^4)^2
3) ... - 16a²b^3 + 16b^6 = (2a^2 - ...)^2
4) 100c^4 + ... +81d^2 = (10c^2 + ...)^2
5) 49p^8 – 56p^4q^3 + ... =(... - ...)^2

ООЧЕНЬ СРОЧНО​

Answer 1

Ответ:

$1)36x {}^{2} - 36xy + 9y {}^{2} = (6x - 3y {}^{2} )$