Question

найдите cos a если cos^4 a- sin^4 a =1/8 с решением пж​

Answer 1

Ответ:

$\cos^{4}( \alpha ) - \sin^{4}( \alpha ) = \frac{1}{8} \\ (\cos^{2}( \alpha ) - \sin^{2} ( \alpha ) )(\cos^{2}( \alpha ) + \sin^{2} ( \alpha ) ) = \frac{1}{8} \\ (\ cos^{2} ( \alpha ) - \sin^{2} ( \alpha ) ) \times 1 = \frac{1}{8} \\ \cos^{2}( \alpha ) - (1 - \cos^{2}( \alpha )) = \frac{1}{8} \\ 2\cos^{2}( \alpha ) - 1 = \frac{1}{8} \\ 2\cos^{2}( \alpha ) = \frac{1}{8} + 1 \\ 2\cos^{2}( \alpha ) = \frac{9}{8} \\ \cos^{2}( \alpha ) = \frac{9}{8} \div 2 \\ \cos^{2}( \alpha ) = \frac{9}{16} \\ \cos ( \alpha ) = \sqrt{ \frac{9}{16} } \\ \cos( \alpha ) = \frac{3}{4}$