Question

Помогите >_< эти четыре примера ​

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Ответ:

№35:

$(\frac{1}{6}+\frac{4}{9} )+\frac{3}{4} *\frac{2}{3} =1\frac{1}{9}.$

1)  $(\frac{1}{6}+\frac{4}{9} )=\frac{1*3+4*2}{18} =\frac{3+8}{18} =\frac{11}{18};$

2)  $\frac{3}{4} *\frac{2}{3} =\frac{3*2}{4*3}=\frac{6}{12}=\frac{1}{2} ;$

3)  $\frac{11}{18} +\frac{1}{2}=\frac{11+1*9}{18} =\frac{11+9}{18} =\frac{20}{18}=\frac{10}{9}=1\frac{1}{9}.$

№36:

$4\frac{2}{3}-3\frac{5}{9}+\frac{7}{12}:\frac{3}{8}=2\frac{2}{3}.$

1)  $4\frac{2}{3}= \frac{3*4+2}{3}=\frac{12+2}{3}=\frac{14}{3};$

2) $3\frac{5}{9}=\frac{9*3+5}{9}=\frac{27+5}{9} =\frac{32}{9};$

3) $\frac{7}{12}:\frac{3}{8}= \frac{7}{12}*\frac{8}{3}= \frac{7*8}{12*3} =\frac{56}{36} =\frac{14}{9};$

4)  $\frac{14}{3}-\frac{32}{9}+\frac{14}{9}= \frac{14}{3}+\frac{-32+14}{9} =\frac{14}{3}+\frac{-18}{9} =\frac{14}{3}+\frac{-6}{3} =\frac{14+(-6)}{3}=\frac{8}{3}=2\frac{2}{3}.$

№37:

$17*\frac{8}{51}-2\frac{4}{9}:3\frac{2}{3}=2.$

1)  $2\frac{4}{9}=\frac{9*2+4}{9}=\frac{18+4}{9}=\frac{22}{9};$

2)  $3\frac{2}{3}= \frac{3*3+2}{3}= \frac{9+2}{3} =\frac{11}{3};$

3)  $17*\frac{8}{51}=1*\frac{8}{3}=\frac{8}{3} ;$

4) $2\frac{4}{9}:3\frac{2}{3}= \frac{22}{9}:\frac{11}{3}=\frac{22}{9}*\frac{3}{11}= \frac{2}{9} *\frac{3}{1}=\frac{2}{3}*\frac{1}{1}=\frac{2}{3};$

5) $\frac{8}{3}-\frac{2}{3}=\frac{8-2}{3} =\frac{6}{3}=2.$

№38:

$5\frac{1}{4}*3\frac{3}{7}:(2\frac{1}{4}*8 ) =1.$

1)  $5\frac{1}{4} =\frac{4*5+1}{4}=\frac{20+1}{4}=\frac{21}{4};$

2) $3\frac{3}{7}=\frac{7*3+3}{7}=\frac{21+3}{7}=\frac{24}{7};$

3) $2\frac{1}{4}=\frac{4*2+1}{4}=\frac{8+1}{4}=\frac{9}{4};$

4) $(\frac{9}{4}*8)=\frac{9}{4}*\frac{8}{1} =\frac{9}{1} *\frac{2}{1} = 9*2=18;$

5) $5\frac{1}{4}*3\frac{3}{7}=\frac{21}{4}*\frac{24}{7}=\frac{3}{4} *\frac{24}{1} =\frac{3*24}{4*1}=\frac{72}{4}=18;$

6) $18:18=1.$