Question

Нужно чтобы получилось 2 способа, с x положительным и x отрицательным ​

Answer 1

$1) \: \: |2x - 7| = - 15 \to \: x \: \in \: \varnothing. \\ \star \: 12x - 71 = - 15 \to12x = - 15 + 71 \to \: 12x = 56 \to \: x = \dfrac{56}{12} = \dfrac{14}{3} = 4 \dfrac{2}{3} \: \star$

$\bf2) \: \: 2.3 - |x| = - 3.8 \to \\ - |x| = - 3.8 - 2.3 \\ - |x| = - 6.1 \\ |x| = 6.1 \\ x = \pm \: 6.1 \to \: \bf \: x _1 = - 6.1 \: \: and \: \: x _2 = 6.1$

$3) \: \: \tt \: 2(x - 48) = - 3(5x - 4) \\ 2x - 96 = - 15x + 12 \\ 2x + 15x = 12 + 96 \\ 17x = 108 \\ x = \frac{108}{17} = 6 \frac{6}{17}$