Question

помогите пожалуйста

Answer 1

$\dfrac{1}{3}\sqrt{144} + 5\sqrt{\dfrac{16}{225}} - (0.2\sqrt{6})^2 = \dfrac{1}{3}\cdot12 + 5\cdot\dfrac{4}{15} - 0.04\cdot6 = 4 + \dfrac{4}{3} - 0.24 = \dfrac{16}{3} - \dfrac{24}{100} = \dfrac{16}{3} - \dfrac{6}{25} = \dfrac{16\cdot25-6\cdot3}{3\cdot25} = \dfrac{382}{75} = 5\dfrac{7}{75}$

$\dfrac{\sqrt{98}}{\sqrt{2}} + \sqrt{150}\sqrt{6} - \sqrt{7^4\cdot3^2} = \sqrt{49} + \sqrt{900} - 7^2\cdot3 = 7 + 30 - 147 = -110$

$2\sqrt{x-1} = 4, \ x \geq1\\\\\sqrt{x-1} = 2\\\\x-1 = 4\\\\x = 5$