Question

Найти log24 72, если log6 2=m

Answer 1

$log_{24} 72 = frac{log_{6} 72}{log_{6} 24} = frac{log_{6} (36*2)}{log_{6} (6*4)} =$

$= frac{2+log_{6} 2}{1+2log_{6}2} = frac{2+m}{1+2m}$