Question

Найдите разность многочленов; 1) (3x - 2) - (-2x + 4) 2) (6y - 1)-(-5 + 5y); 3) (3x²– x)-(-x + 2x²) 4) (6y +y²) - (-4y+y²); 5) (-9x – 3+х²) - (4х – 3+ х²); 6) (8y² - 6y + 4) - (5 + 7y² + 6y)​

Answer 1

$1) (3x - 2) - ( - 2x + 4) = 3x - 2 + 2x - 4 = 5x - 6 \\ 2) (6y - 1) - ( - 5 + 5y) = 6y - 1 + 5 - 5y = - y + 4 \\ 3) (3 {x}^{2} - x) - ( - x + 2 {x}^{2} ) = 3 {x}^{2} - x + x - 2 {x}^{2} = {x}^{2}$