Question

номер 354 Помогите пожалуйста!!? ​

Answer 1

№354

$\displaystyle\\1)18*(\frac{1}{3}-\frac{1}{9} )=18*( \frac{3}{9}-\frac{1}{9})=18*\frac{2}{9}=\frac{18*2}{9}=\frac{2*2}{1} =2*2=4\\\\\\\\2)(2-\frac{3}{4}-\frac{4}{5})*20=(\frac{40}{20}-\frac{15}{20}-\frac{16}{20})*20=\frac{9}{20}*20=\frac{9*20}{20}=\frac{9*1}{1}=9\\\\\\\\3)(1-\frac{1}{3} -\frac{1}{6} -\frac{1}{9} )*18=(\frac{18}{18}-\frac{6}{18}-\frac{3}{18}-\frac{2}{18})*18= \frac{7}{18}*18=\frac{7}{1}*1=7$

$\displaystyle\\4)(\frac{5}{6} +\frac{5}{9})*\frac{18}{25}=(\frac{15}{18}+\frac{10}{18})*\frac{18}{25}=\frac{25}{18}*\frac{18}{25}=\frac{1}{1} *\frac{1}{1} =1$