Question

Решить уравнени 1)9^ x+1 =27 sqrt 3 ;

Answer 1

$\displaystyle\bf\\9^{x+1} =27\sqrt{3} \\\\(3^{2} )^{x+1} =3^{3}\cdot 3^{\frac{1}{2} } \\\\3^{2x+2} =3^{3,5} \\\\2x+2=3,5\\\\2x=1,5\\\\x=0,75$