Предмет: Химия, автор: cracken1

допоможіть вирішити задачу, будь ласка
Обчисліть практичний вихід амоніаку, якщо, подіявши на амоній сульфат масою 13,2г надлишком лугу, одержали амоніак об'ємом 2л (н. у.)

Ответы

Автор ответа: dnepr1
0
Взаємодія з лугами (у розчині відбувається дуже швидко):
 (NH4)2SO4 + 2КОН = К2SO4 + 2NH4ОН
  2 NH4+ + SO42- + 2К+ + 2ОН– = 2К+ + SO42- + 2NH3 + 2Н2О
  2 NH4+ + 2ОН– = 2NH3 _+ 2Н2О

  NH4+ + ОН– = NH3  + Н2О
Амоніак, який виділяється при цьому, виявляють за допомогою зволоженого індикаторного папірця.
Молярна маса
амоній сульфату: (14+4*1)*2+32+16*4 = 132 г/моль.
Вихід амоніаку - 2 моля, тобто 2*22,4 = 44,8 л.
Складаємо пропорцію:  132 г - 44,8 л
                                             13,2 г - х л        х = 13,2*44,8 / 132 = 4,48 л.
Вихід: 2*100 / 4,48 =
44,64%


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