Question

Вычислить выражение (спасибо)

Answer 1

$\displaystyle(\sqrt[6]{27}+\sqrt[4]{64})(\sqrt[6]{27}-\sqrt[4]{64})=27^\frac16\cdot27^\frac16-27^\frac16\cdot64^\frac14+64^\frac14\cdot27^\frac16-64^\frac14\cdot64^\frac14=$

$\displaystyle=27^\frac13-64^\frac14(27^\frac16-27^\frac16)-64^\frac12=\sqrt[3]{27}-64^\frac14(27^\frac16-27^\frac16)-\sqrt{64}=$

$\displaystyle=3-64^\frac14\cdot0-8=3-8=-5$