Question

7/5:1 2/5+1 2/5*2/5-1:1 3/5​

Answer 1

Решение:

$\dfrac{7}{5} : 1\dfrac{2}{5} + 1\dfrac{2}{5} \cdot \dfrac{2}{5} -1 : 1\dfrac{3}{5} =\dfrac{187}{200}$

$1)~~\dfrac{7}{5} : 1\dfrac{2}{5} = \dfrac{7}{5} : \dfrac{7}{5} = 1$

$2)~~1\dfrac{2}{5} \cdot \dfrac{2}{5} = \dfrac{7}{5} \cdot \dfrac{2}{5} =\dfrac{14}{25}$

$3)~~1 : 1\dfrac{3}{5} =1 :\dfrac{8}{5} = \dfrac{5}{8}$

$4)~~ 1 + \dfrac{14}{25} = 1\dfrac{14}{25}$

$5)~~ 1\dfrac{14}{25} -\dfrac{5}{8} =1\dfrac{112}{200} -\dfrac{125}{200} =\dfrac{312}{200} -\dfrac{125}{200} =\dfrac{187}{200}$