Question

Алгебра соч помогите​

Answer 1

Ответ:

$\Big(\dfrac{7}{8}\Big)^{-2}-\Big(-\dfrac{3}{8}\Big)^0+\Big(\dfrac{7}{3}\Big)^2:\dfrac{7}{9}=\Big(\dfrac{8}{7}\Big)^2-1+\dfrac{7^2}{3^2}\cdot \dfrac{9}{7}=\dfrac{64}{49}-1+\dfrac{7}{1}=\dfrac{64}{49}+6=\\\\\\=\dfrac{358}{49}=7\dfrac{15}{49}$

Answer 2

Объяснение:

$( \frac{7}{8} ) {}^{ - 2} - ( - \frac{3}{8} ) {}^{0} + ( \frac{7}{3} ) {}^{2} \div \frac{7}{9} = \frac{64}{49}-\left(-\frac{3}{8}\right)^{0}+\frac{\left(\frac{7}{3}\right)^{2}}{\frac{7}{9}} =\frac{64}{49}-1+\frac{\left(\frac{7}{3}\right)^{2}}{\frac{7}{9}} =\frac{15}{49}+\frac{\left(\frac{7}{3}\right)^{2}}{\frac{7}{9}} =\frac{15}{49}+\frac{\frac{49}{9}}{\frac{7}{9}} =\frac{15}{49}+\frac{49}{9}\times \left(\frac{9}{7}\right) =\frac{15}{49}+7 =\frac{358}{49} = 7\frac{15}{49}$