Question

Помогите пожалуйста!

Answer 1

$\displaystyle\bf\\y=\sqrt{x} \\1)\\A(a \ ; \ 2\sqrt{7} ) \ \Rightarrow \ x=a \ ; \ y=2\sqrt{7} \\\\2\sqrt{7} =\sqrt{a} \\\\(2\sqrt{7} )^{2} )=(\sqrt{a} )^{2} \\\\a=4\cdot 7=28\\\\a=28\\\\2)\\x\in[0 \ ; \ 16]\\\\y=\sqrt{0} =0\\\\y=\sqrt{16} =4\\\\y\in[0 \ ; \ 4]\\\\3)\\y\in[8 \ ; \ 23]\\\\8=\sqrt{x} \\\\x=8^{2} =64\\\\23=\sqrt{x} \\\\x=23^{2} =529\\\\x\in[64 \ ; \ 529]\\\\4)\\y\leq 7\\\\\sqrt{x} \leq 7\\\\x\leq 49$