Question

помогите пожалуйста ​

Answer 1

$\frac{ {a }^{2} - 1 }{a - 5} = \frac{ { - 3}^{2} - 1}{ - 3 - 5} = \frac{ 9 - 1}{ - 8} = \frac{8}{ - 8} = - 1$

$\frac{16b}{ {20b}^{4} } = \frac{4}{ {5b}^{3} }$

$\frac{4x - 16}{ {x}^{2} - 16} = \frac{4(x - 4)}{(x - 4)(x + 4)} = \frac{4}{x + 4}$

$\frac{ {12y}^{ 3} - {8y}^{2} }{2 - 3y} = \frac{ {4y}^{2} (3y - 2)}{ - (3y - 2)} = \frac{ {4y}^{2} }{ - 1}$