Question

обчислыть:cos135·tg45+sin150

Answer 1

$\displaystyle\tt \cos135 {}^{ \circ} \cdot \tg45 {}^{ \circ} + \sin150 {}^{ \circ} = - \frac{ \sqrt{2} }{2} \cdot1 + \dfrac{1}{2} = - \frac{ \sqrt{2} }{2} + \frac{1}{2} = \frac{ - \sqrt{2} + 1}{2} .$