Question

СРОЧНО ДАЮ 20 БАЛЛОВ

Answer 1

$( \frac{b}{b-c}+ \frac{bc}{c^2-b^2} )* \frac{c^2-2bc+b^2}{b^2} =\\( \frac{bc}{(c-b)(c+b)}- \frac{b}{c-b} )* \frac{(c-b)^2}{b^2} =\\( \frac{bc-b(c+b)}{(c-b)(c+b)} )* \frac{(c-b)^2}{b^2} = \frac{-b^2}{(c-b)(c+b)} * \frac{(c-b)^2}{b^2} =\\ \frac{(-b^2)(c-b)^2}{(c-b)(c+b)b^2} = \frac{b-c}{c+b}$
Ответ: $\frac{b-c}{b+c}$