Question

dx/(1-x)ln^2(1-x) integral

Answer 1

Ответ:

$\int\limits {\frac{dx }{(1-x)ln^{2}(1-x) } } \, =-\int\limits {\frac{d(1-x) }{(1-x)ln^{2}(1-x) } } \, =-\int\limits {\frac{d(ln(1-x)) }{ln^{2}(1-x) } } \,=-\frac{ln^{-2+1}(1-x)}{-2+1} =\frac{1}{ln(1-x)} +C$

Объяснение:

$\frac{1}{ln(1-x)} +C$