Question

ПОМОГИТЕ с алгеброй пожалуйста​

Answer 1

Ответ:

$\left\{\begin{array}{l}\dfrac{1}{x+y}+\dfrac{1}{x-y} =2\\\dfrac{3}{x+y}+\dfrac{4}{x-y}=7\end{array}\right\ \ \ \ \left\{\begin{array}{l}t=\dfrac{1}{x+y}\\p=\dfrac{1}{x-y}\end{array}\right\ \ \ \ \left\{\begin{array}{l}t+p=2\ |\cdot (-3)\\3t+4p=7\end{array}\right\ \oplus \\\\\\\\\left\{\begin{array}{l}t+p=2\\p=1\end{array}\right\ \ \ \ \left\{\begin{array}{l}t=2-p\\p=1\end{array}\right\ \ \ \ \left\{\begin{array}{l}t=1\\p=1\end{array}\right$

$\left\{\begin{array}{l}\dfrac{1}{x+y}=1\\\dfrac{1}{x-y}=1\end{array}\right\ \ \left\{\begin{array}{l}x+y=1\\x-y=1\end{array}\right\ \oplus \ominus \ \left\{\begin{array}{l}2x=2\\2y=0\end{array}\right\ \ \left\{\begin{array}{l}x=1\\y=0\end{array}\right\\\\\\Otvet:\ (\ 1\ ;\ 0\ )\ .$