Question

5 V 6.4. Вычислите: 1) 2-3: 2)(-3); 3) (-1)-2. 3 2 4) с | ; 5) 0,02- 6) 1,25 : 7)-4-3, 8) (-0,3); 9) (-2 12)-(-2 10) (-2,25)-1; 11)-(-2,3)-1; 12 B​

Answer 1

Ответ:

$2^{-3}=\dfrac{1}{2^3}=\dfrac{1}{8}\\\\(-3)^{-3}=\dfrac{1}{(-3)^3}=-\dfrac{1}{27}\\\\\displaystyle (-1)^{-22}=\frac{1}{(-1)^{22}}=\dfrac{1}{1}=1\\\\\Big(\frac{2}{5}\Big)^3=\frac{2^3}{5^3}=\frac{8}{125}\\\\(0,02)^{-3}=\Big(\frac{2}{100}\Big)^{-3}=\Big(\frac{100}{2}\Big)^3=50^3=125000\\\\1,25^{-2}=\Big(1\frac{1}{4}\Big)^{-2}=\Big(\frac{5}{4}\Big)^{-2}=\Big(\frac{4}{5}\Big)^2=\frac{4^2}{5^2}=\frac{16}{25}\\\\(-4)^{-3}=\frac{1}{(-4)^3}=-\frac{1}{64}$

$\displaystyle (-0,3)^{-2}=\Big(-\frac{3}{10}\Big)^{-2}=\Big(-\frac{10}{3}\Big)^2=\frac{100}{9}=11\frac{1}{9}\\\\\Big(-2\frac{1}{2}\Big)^{-3}=\Big(-\frac{5}{2}\Big)^{-3}=\Big(-\frac{2}{5}\Big)^3=-\frac{8}{125}\\\\(-2,25)^{-1}=\Big(-\frac{9}{4}\Big)^{-1}=-\frac{4}{9}\\\\-(-2,3)^{-1}=-\Big(-\frac{23}{10}\Big)^{-1}=-\Big(-\frac{10}{23}\Big)=\frac{10}{23}\\\\-\Big(-2\frac{1}{3}\Big)^{-2}=-\Big(-\frac{7}{3}\Big)^{-2}=-\Big(-\frac{3}{7}\Big)^2=-\frac{9}{49}$