Question

Алгебра 10 класс, дроби.

Answer 1

$f(x)=\dfrac{x}{2x-1} \\\\\\f'(x)=\dfrac{x'\cdot(2x-1)-x\cdot(2x-1)'}{(2x-1)^{2} } =\dfrac{2x-1-2x}{(2x-1)^{2} }=-\dfrac{1}{(2x-1)^{2} }\\\\\\f'(0)=-\dfrac{1}{(2\cdot 0-1)^{2} }=-\dfrac{1}{1}=-1\\\\\\f'(-2)=-\dfrac{1}{(2\cdot(-2)-1)^{2} } =-\dfrac{1}{25}=-0,04\\\\\\f'(0)-f'(-2)=-1-(-0,04)=-1+0,04=\boxed{-0,96}$