Question

Решите систему уравнений

Answer 1

Ответ:

$\left \{ {{x^{3} +x^{2} y=12} \atop {x+y=3}} \right. \\\left \{ {{x^{2}( x+ y)=12} \atop {x+y=3}} \right. \\\left \{ {{3x^{2}=12} \atop {x+y=3}} \right. \\\\\left \{ {{x^{2}=4} \atop {x+y=3}} \right. \\1) \left \{ {{x=2} \atop {x+y=3}} \right. \\\left \{ {{x=2} \atop {y=1}} \right. \\2)\left \{ {{x=-2} \atop {x+y=3}} \right. \\\\2)\left \{ {{x=-2} \atop {y=5}} \right.$

Объяснение: