Question

и еще
4) t^(39)
9^(39)​

Answer 1

Ответ:

По свойству степеней: аⁿ/bⁿ= (a/b)ⁿ

1) (4/х)^10

2) (7/y)^13

3) (z/6)^21

4) (t/9)^39

Answer 2

$1) \ \dfrac{4^{10} }{x^{10} } =\Big(\dfrac{4}{x}\Big)^{10}\\\\\\2) \ \dfrac{7^{13} }{y^{13} } =\Big(\dfrac{7}{y}\Big)^{13}\\\\\\3) \ \dfrac{z^{21} }{6^{21} } =\Big(\dfrac{z}{6}\Big)^{21}\\\\\\4) \ \dfrac{t^{39} }{9^{39} } =\Big(\dfrac{t}{9}\Big)^{39}$