Предмет: Геометрия, автор: madinazusopova

средняя линия авс равна 4см найдите площадь пароллерограмма абсд если ад равна 10

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Автор ответа: ViktoriaPobloki

0

Средняя линия треугольника -

Отрезок, соединяющий середины двух его сторон, параллельный третьей стороне, равный её половине; ⇒ если NM - средняя линия ΔABD и MN=4, то сторона ВD ΔАВD=4*2=8см;

Sпараллелограмма=аh (основание*высота);

10*8=80см²

Ответ: 80см²

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