Question

(93+x)-15=
59-(m+27)=
(y+327)-100=
429-(311+k)=

Answer 1

(93 + х) - 15 = 93 + х - 15 = х + (93 - 15) = х + 78

59 - (m + 27) = 59 - m - 27 = (59 - 27) - m = 32 - m

(у + 327) - 100 = у + (327 - 100) = у + 227

429 - (311 + k) = 429 - 311 - k = 118 - k

Answer 2

Ответ:

$(93+x)-15=(93-15)+x=78+x\\\\\\59-(m+27)=(59-27)-m=32-m\\\\\\(y+327)-100=y+(327-100)=y+227\\\\\\429-(311+k)=(429-311)-k=118-k$