Question

Система уравнений
y-xy+3x=-3
2y+xy-x=2

Answer 1

$+\left\{\begin{array}{ccc}y-xy+3x=-3\\2y+xy-x=2\end{array}\right \\-----------\\ \ \ 3y+2x=-1\\\\2x=-3y-1\\\\x=-1,5y-0,5\\\\\\\left\{\begin{array}{ccc}x=-1,5y-0,5\\2y+(-1,5y-0,5)\cdot y-(-1,5y-0,5)=2\end{array}\right \\\\\\\left\{\begin{array}{ccc}x=-1,5y-0,5\\2y-1,5y^{2} -0,5y+1,5y+0,5=2\end{array}\right\\\\\\\left\{\begin{array}{ccc}x=-1,5y-0,5\\1,5y^{2}-3y+1,5=0|:1,5\end{array}$

$\left\{\begin{array}{ccc}x=-1,5y-0,5\\y^{2}-2y+1=0\end{array}\right\\\\y^{2}-2y+1=0\\\\(y-1)^{2}=0\\\\y-1=0\\\\y=1\\\\x=-1,5 \cdot 1-0,5=-1,5-0,5=-2\\\\Otvet:\boxed{(-2 \ ; \ 1)}$