Question

Помогите решить
2y² + 3 1/3y= 18 2/3

Answer 1

$2y^{2}+3\dfrac{1}{3} y=18\dfrac{2}{3} \\\\2y^{2}+\dfrac{10}{3}y-\dfrac{56}{3}=0 \\\\2y^{2}\cdot 3+\dfrac{10}{3}y\cdot 3-\dfrac{56}{3}\cdot 3=0\\\\6y^{2}+10y-56=0\\\\3y^{2}+5y-28=0\\\\D=5^{2}-4\cdot 3\cdot (-28)=25+336=361=19^{2}\\\\y_{1}=\dfrac{-5-19}{6} =-4\\\\y_{2}=\dfrac{-5+19}{6} =2\dfrac{1}{3}\\\\Otvet:\boxed{-4 \ ; \ 2\dfrac{1}{3}}$