Question

системное уравнение​

Answer 1

$\left \{ {{10x-6y=3} \atop {9x-2y=12|\cdot(-3)}} \right.\\\\+\left \{ {{10x-6y=3} \atop {-27x+6y=-36}} \right.\\ --------\\-17x=-33\\\\x=1\frac{16}{17} \\\\2y=9x-12=9\cdot\frac{33}{17} -12=17\frac{8}{17}-12=5\frac{8}{17} \\\\y=5\frac{8}{17} :2=2\frac{25}{34} \\\\Otvet:\boxed{\Big(1\frac{16}{17} \ ; \ 2\frac{25}{34}\Big)}$