Question

Помогите с алгеброй: 

$(x-1)^{4} -x^{2}+2x-73=0$

Answer 1

$(x-1)^{4} -x^{2}+2x-73=0 \ (x-1)^{4} -x^{2}+2x-1-72=0 \ (x-1)^{4} -(x-1)^2-72=0 \ a^2 -a-72=0 \ D=1+288=289 \ a_1= frac{1-17}{2} =-8 \ a_1= frac{1+17}{2} =9 \ (x-1)^2 neq -8 \ (x-1)^2=9 \ left { {{x-1= 3 } atop {x-1=-3 }} right. \ left { {{x=1+3=4} atop {x=1- 3=-2 }} right.$
Ответ: 4 и -2