Question

Реши уравнение 4t+4−t3−t2=0. t1= t2= t3=

Answer 1

Объяснение:

$4t + 4 - t {}^{3} - t {}^{2} = 0 \\ 4(t + 1) - t {}^{2} (t + 1) = 0 \\ (4 - t {}^{2} )(t + 1) = 0$

1)

$4 - t {}^{2} = 0 \\ t {}^{2} = 4 \\ t = + - 2$

2)

$t + 1 = 0 \\ t = - 1$

ответ:

$t1 = - 2 \\ t2 = - 1 \\ t3 = 2$