Question

Решите задние №4 под буквой б из второго варианта!

Answer 1

$frac{22}{1+sqrt{27}-sqrt3}=frac{22}{1+sqrt{9*3}-sqrt3}=frac{22}{1+3sqrt3-sqrt3}=frac{22}{1+2sqrt3}= \ =frac{22(1-2sqrt3)}{(1+2sqrt3)(1-2sqrt3)}=frac{22(1-2sqrt3)}{1^2-(2sqrt3)^2}=frac{22(1-2sqrt3)}{1-12}=frac{22(1-2sqrt3)}{-11}= \ =-2(1-2sqrt3)=-2+4sqrt3$