Предмет: Математика, автор: slavikkoz2009

5. Из вершины развернутого угла мкс, изображенного на
рисунке, проведены лучи KA и КВ так, что MKB = 175°,
AKC = 118°. Вычислите градусную меру угля АКВ.

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Приложения:

Ответы

Автор ответа: glebeveryone
6

Ответ:

113°

Пошаговое объяснение:

BKC = 180°-175° = 5° (как смежный с MKB = 175°)

AKM = 180°-118° = 62° (как смежный с AKC = 118°)

AKB = 180° - AKM - BKC = 180° - 5° - 62° = 113°

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