Question

помогите пожалуйста.​

Answer 1

Ответ:

1

1.

$F(x) = \int\limits \sqrt{7} dx = \sqrt{7}x + C$

2.

$F(x) = \int\limits {x}^{11} dx = \frac{ {x}^{12} }{12} + C$

3.

$F(x) = \int\limits \frac{dx}{ {x}^{5} } = \int\limits {x}^{ - 5} dx = \\ = \frac{ {x}^{ - 4} }{ - 4} + C = - \frac{1}{4 {x}^{4} } + C$

4.

$F(x) = \int\limits( {x}^{8} - 3 {x}^{7} - 5x + 2)dx = \frac{ {x}^{9} }{9} - \frac{3 {x}^{8} }{8} - \frac{5 {x}^{2} }{2} + 2x + C$

5.

$F(x) = \int\limits( - \frac{5}{ \cos {}^{2} (x) } - \frac{2x}{ 3} )dx = \\ = - 5tgx - \frac{2}{3} \times \frac{ {x}^{2} }{2} + C = - 5tgx - \frac{ {x}^{2} }{3} + C$

6.

$F(x) = \int\limits(4x - 5) {}^{2} dx = \\ = \frac{1}{4} \int\limits(4x - 5) {}^{2} d(4x - 5) = \frac{ {(4x - 5)}^{3} }{12} + C$

2

$F(x) = \int\limits(3 {x}^{2} - 8 {x}^{3} + 5)dx = \frac{3 {x}^{3} }{3} - \frac{8 {x}^{4} }{4} + 5x + C = \\ = {x}^{3} - 2 {x}^{4} + 5x + C$

В точке М

$10 = - 8 - 2 \times 16 - 10 + C \\ C = 18 + 32 + 10 = 60$

$F(x) = {x}^{3} - 2 {x}^{4} + 5x + 60$