Question

(6x−18)^2−4(6x−18)+3=0

Answer 1

$(6x-18)^{2}-4(6x-18)+3=0\\\\6x-18=m\\\\m^{2} -4m+3=0\\\\m_{1}=1\\\\m_{2}=3-teorema \ Vieta\\\\1)6x-18=1\\\\6x=19\\\\x_{1}=3\frac{1}{6}\\\\2)6x-18=3\\\\6x=21\\\\x_{2}=3,5\\\\\boxed{x_{1}=3\frac{1}{6} \ ; \ x_{2} =3,5}$